(4y-3)(2y^2+3y-5)=

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Solution for (4y-3)(2y^2+3y-5)= equation: 


Simplifying
(4y + -3)(2y2 + 3y + -5) = 0

Reorder the terms:
(-3 + 4y)(2y2 + 3y + -5) = 0

Reorder the terms:
(-3 + 4y)(-5 + 3y + 2y2) = 0

Multiply (-3 + 4y) * (-5 + 3y + 2y2)
(-3(-5 + 3y + 2y2) + 4y * (-5 + 3y + 2y2)) = 0
((-5 * -3 + 3y * -3 + 2y2 * -3) + 4y * (-5 + 3y + 2y2)) = 0
((15 + -9y + -6y2) + 4y * (-5 + 3y + 2y2)) = 0
(15 + -9y + -6y2 + (-5 * 4y + 3y * 4y + 2y2 * 4y)) = 0
(15 + -9y + -6y2 + (-20y + 12y2 + 8y3)) = 0

Reorder the terms:
(15 + -9y + -20y + -6y2 + 12y2 + 8y3) = 0

Combine like terms: -9y + -20y = -29y
(15 + -29y + -6y2 + 12y2 + 8y3) = 0

Combine like terms: -6y2 + 12y2 = 6y2
(15 + -29y + 6y2 + 8y3) = 0

Solving
15 + -29y + 6y2 + 8y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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